1+(36/x^2)=12/x

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Solution for 1+(36/x^2)=12/x equation:


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

36/(x^2)+1 = 12/x // - 12/x

36/(x^2)-(12/x)+1 = 0

36/(x^2)-12*x^-1+1 = 0

36*x^-2-12*x^-1+1 = 0

t_1 = x^-1

36*t_1^2-12*t_1^1+1 = 0

36*t_1^2-12*t_1+1 = 0

DELTA = (-12)^2-(1*4*36)

DELTA = 0

t_1 = 12/(2*36)

t_1 = 1/6 or t_1 = 1/6

t_1 = 1/6

x^-1-1/6 = 0

1*x^-1 = 1/6 // : 1

x^-1 = 1/6

-1 < 0

1/(x^1) = 1/6 // * x^1

1 = 1/6*x^1 // : 1/6

6 = x^1

x = 6

t_1 = 1/6

x^-1-1/6 = 0

1*x^-1 = 1/6 // : 1

x^-1 = 1/6

-1 < 0

1/(x^1) = 1/6 // * x^1

1 = 1/6*x^1 // : 1/6

6 = x^1

x = 6

x in { 6, 6 }

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